Dean Wade reportedly signs a three-year $18.5 million contract extension deal with Cavaliers

Cleveland Cavaliers were looking to extend their contract with power forward Dean Wade for quite some time after signing him on a two-way contract in 2019 and after a promising start to his life with the cavaliers, yesterday,  Cleveland Cavaliers officially announced the extension of the forward.

According to Wojnarowski, citing Wade’s agents, the agreement was for three years and $18.5 million. 
In June, the Cavs triggered a fourth-year option on his deal.

“Undrafted to extended” Cavaliers tweeted on their official announcement tweet yesterday. 

Wade, a Kansas native who was a standout for K-State under head coach Bruce Weber from 2015 to 2019, went undrafted in the 2019 NBA Draft but later signed with Cleveland. After spending most of the first season with the Cavaliers’ G League affiliate, the Canton Charge, wade gradually became a regular for the Cavaliers in NBA in the 20-21 season.

In his breakthrough season, Wade averaged 6.0 points per game.

Through three seasons, Wade appeared in 126 NBA games, starting 47 of them. He averaged 5.3 points, 2.9 rebounds, and 1 assist per game last season.

However, he had to miss the last 15 games of the season due to a knee injury. Despite that, Wade’s growing potential and last two seasons’ performance have convinced the Cavaliers to hold on to the forward. 


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